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Home/ Questions/Q 8200233
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T06:22:19+00:00 2026-06-07T06:22:19+00:00

i have a paragraph in the database its like $str =this is a paragraph

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i have a paragraph in the database its like

$str =”this is a paragraph i show shortly and when i click on the view more it will show completely for that i am using the ajax and retrieve it “

i show this like

this is a paragraph i show shortly

php for show the first some word is

function chop_string($str, $x)// i called the function  
{
    $string = strip_tags(stripslashes($string)); 
    return substr($string, 0, strpos(wordwrap($string, $x), "\n"));
}

and when user click on the view more it will display rest of it but the problem it that how to skip this this is a paragraph i show shortly and show the rest of it

i want to show the paragraph after the $x on click on view more

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-07T06:22:22+00:00Added an answer on June 7, 2026 at 6:22 am

    I have made an example here: shaquin.tk/experiments/showmore.html.

    You can view the source to see all of the code behind it. The PHP code is displayed on the page.

    If you don’t want to display the start string when Show more is clicked, replace the JavaScript function showMore with this:

    function showMore() {
        if(state == 0) {
            state = 1;
            document.getElementById('start').style.display = 'none';
            document.getElementById('end').style.display = 'block';
            document.getElementById('showmore').innerHTML = 'Show less';
            document.getElementById('text-content').className = 'expanded';
            document.getElementById('start').className = 'expanded';
        } else {
            state = 0;
            document.getElementById('start').style.display = 'block';
            document.getElementById('end').style.display = 'none';
            document.getElementById('showmore').innerHTML = 'Show more';
            document.getElementById('text-content').className = '';
            document.getElementById('start').className = '';
        }
    }
    

    Hope this helps.

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