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Home/ Questions/Q 8289977
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T12:39:35+00:00 2026-06-08T12:39:35+00:00

I have a PHP data structure I want to JSON encode. It can contain

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I have a PHP data structure I want to JSON encode. It can contain a number of empty arrays, some of which need to be encoded as arrays and some of which need to be encoded as objects.

For instance, lets say I have this data structure:

$foo = array(
  "bar1" => array(), // Should be encoded as an object
  "bar2" => array() // Should be encoded as an array
);

I would like to encode this into:

{
  "bar1": {},
  "bar2": []
}   

But if I use json_encode($foo, JSON_FORCE_OBJECT) I will get objects as:

{
  "bar1": {},
  "bar2": {}
}

And if I use json_encode($foo) I will get arrays as:

{
  "bar1": [],
  "bar2": []
}

Is there any way to encode the data (or define the arrays) so I get mixed arrays and objects?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T12:39:36+00:00Added an answer on June 8, 2026 at 12:39 pm

    Create bar1 as a new stdClass() object. That will be the only way for json_encode() to distinguish it. It can be done by calling new stdClass(), or casting it with (object)array()

    $foo = array(
      "bar1" => new stdClass(), // Should be encoded as an object
      "bar2" => array() // Should be encoded as an array
    );
    
    echo json_encode($foo);
    // {"bar1":{}, "bar2":[]}
    

    OR by typecasting:

    $foo = array(
      "bar1" => (object)array(), // Should be encoded as an object
      "bar2" => array() // Should be encoded as an array
    );
    
    echo json_encode($foo);
    // {"bar1":{}, "bar2":[]}
    
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