Question

I have a problem and then I need your help to solve it.

I have a matrix A

A = [ 0 0 1 2 3 4 0;
      1 2 3 4 0 0 0;
      0 0 0 1 2 3 4;
      0 1 2 3 4 0 0]

and then I want to know how many number of each values “1” of each rows in matrix A which is not in the same column with each value “>=3” of each rows in matrix A.

so I wish that my answer

Ans = 2

Thanks before.

Answer 1

Try this:

>> num = sum( any(A(:,all(A<3))==1,2) )
num =
     2

First we find the columns indices containing no values greater or equal to 3 idx = all(A<3).

Next in those columns A(:,idx), we find the rows containing any 1: any(A(:,idx)==1,2).

Finally we count how many such rows were found sum(.)