Question

I have a problem understanding how the try{} catch(Exception e){...} works!

Let’s say I have the following:

try
{
    while(true)
    {
        coord = (Coordinate)is.readObject();//reading data from an input stream
    }
}
catch(Exception e)
{
    try{
        is.close();
        socket.close();
    }
    catch(Exception e1)
    {
        e1.printStackTrace();
    }
}

Section 2

    try
    {
        is.close();
        db.close();
    }
    catch(Exception e)
    {
        e.printStackTrace();
    }

Let’s say my while() loop throws an error because of an exception of is stream.

This will get me out of the infinite loop and throw me in the first catch(){............}
block.

My question is the following:

After throwing an exception, getting out of the loop while() and reaching to

catch(){ 
}

Will my program continue his execution and move on to section 2? As long as the exception was caught? Or everything ends in the first catch()?

Answer 1

I think you want to use finally after your first catch [catch (Exception e)] to close your streams:

try {
    // Do foo with is and db
} catch (Exception e) {
    // Do bar for exception handling
} finally {
    try {
        is.close();
        db.close();
    } catch (Exception e2) {
      // gah!
    }
}