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Home/ Questions/Q 6090915
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T12:16:06+00:00 2026-05-23T12:16:06+00:00

I have a project built in Python 2.7, using SQLite3 as the database. I

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I have a project built in Python 2.7, using SQLite3 as the database. I need to know how to load an item from a particular row and column into an existing Python variable.

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  1. Editorial Team
    Editorial Team
    2026-05-23T12:16:06+00:00Added an answer on May 23, 2026 at 12:16 pm

    Here are the basic steps:

    import sqlite3
    conn = sqlite3.connect(':memory:')
    curs = conn.cursor()
    results = curs.execute( """SELECT mycol 
                                 FROM mytable 
                                WHERE somecol = ?;""", (some_var,) ).fetchall()
    curs.close()
    conn.close()
    

    For further research you can look into using a context manager (with statement), and how to fetch results into a dict. Here’s an example:

    with sqlite3.connect(':memory:') as conn:
        curs = conn.cursor()
        curs.row_factory = sqlite3.Row
        try:
            results = curs.execute( """SELECT mycol 
                                         FROM mytable 
                                        WHERE somecol = ?;""", 
                                   (some_var,) ).fetchall()
        # you would put your exception-handling code here
        finally:
            curs.close()
    

    The benefits of the context manager are many, including the fact that your connection is closed for you. The benefit of mapping the results in a dict is that you can access column values by name as opposed to a less-meaningful integer.

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