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Home/ Questions/Q 1063519
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T18:47:40+00:00 2026-05-16T18:47:40+00:00

I have a question regarding Interface. There are 2 interface both contain the same

  • 0

I have a question regarding Interface. There are 2 interface both contain the same Method Test().
Now I’m inheriting both the interface in Sample class.I want to know which Interface’s method will be called?
My code sample is below:

interface IA 
{
    void Test();
}
interface IB
{
    void Test();
}
class Sample: IA, IB
{
    public void Test()
    {
      Console.WriteLine("Which interface will be implemented IA or IB???!");
    }
}
class Program
{
    public static void Main(string[] args)
    {
        Sample t = new Sample();
        t.Test();//Which Interface's Method will called.
        Console.ReadLine();
    }
}

Thanks
Vijendra Singh

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T18:47:41+00:00Added an answer on May 16, 2026 at 6:47 pm

    The result will be the same for both. If you want different behaviour per interface, you have to explicitly implement them:

    interface IA 
    {
        void Test();
    }
    interface IB
    {
        void Test();
    }
    class Sample: IA, IB
    {
        void IA.Test()
        {
          Console.WriteLine("Hi from IA");
        }
        void IB.Test()
        {
          Console.WriteLine("Hi from IB");
        }
        public void Test() //default implementation
        {
          Console.WriteLine("Hi from Sample");
        }
    }
    
    class Program
    {
        public static void Main(string[] args)
        {
            Sample t = new Sample();
            t.Test(); // "Hi from Sample"
            ((IA)t).Test(); // "Hi from IA"
            ((IB)t).Test(); // "Hi from IB"
            Console.ReadLine();
        }
    }
    

    If you want default behaviour, create a method with the same signature (thus an implicit interface implementation) and add code for that case. Usually, you just want the explicit implementation though.

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