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Home/ Questions/Q 8307891
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T18:38:25+00:00 2026-06-08T18:38:25+00:00

I have a String s = ‘muniganesh’ and if I print the value of

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I have a String s = 'muniganesh' and if I print the value of s.subString(1, 2), the output is 'u', because in Java strings, the index starts at 0. But I need to change my string to start with index position 1. How is it possible?

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  1. Editorial Team
    Editorial Team
    2026-06-08T18:38:26+00:00Added an answer on June 8, 2026 at 6:38 pm

    You could write your own utility method to process both #substring(start, end) arguments as zero-based indexes (or one-based indexes if you wish so), but as @irrelephant said it is not suggested, you should get accustomed to how Java handles these special cases: the first argument is zero-based, while the second one is one-based. String#substring is not the only example, there’s also StringBuilder#delete, and there should be more.

    The possible motivation could be calculating end position by simply adding length to the start position without additional increment. E.g.:

        String source = "In Java world, end position index may be one-based";
        int indexOfP = source.indexOf('p');
        String result = source.substring(indexOfP, indexOfP + 8);
        System.out.println(result); // prints 'position'
    

    It’s not the best example, and the true motivation may differ, but it’s how I remember about this peculiarity.

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