Question

I have a string something like:

foo title:2012-01-01 bar

Where I need to get the ‘title:2012-01-01’ and replace the date part ‘2012-01-01’ to a special format. I just am not good at RegExp and currently have:

'foo from:2012-01-01 bar'.replace(/from:([a-z0-9-]+)/i, function() {
    console.log(arguments);
    return 'replaced';
})

and that returns

foo replaced bar 

which is a start but not exactly correct. I need the ‘from:’ not to be replaced, just the ‘2012-01-01’ be replaced. Tried using (?:from:) but that didn’t stop it from replacing ‘from:’. Also, I need to take into account that there may be a space between ‘from:’ and ‘2012-01-01’ so it needs to match this also:

foo title: 2012-01-01 bar

Answer 1

The following should do what you need it to; tested it myself:

'foo from:2012-01-01 bar'.replace(/(\w+:\s?)([a-z0-9-]+)/i, function(match, $1) {
    console.log(arguments);
    return $1 + 'replaced';
});

DEMO

It will match both title: etc and from:etc. The $1 is the first matched group, the (\w+:\s?), the \w matches any word character, while the \s? matches for at least one or no spaces.