Question

I have a string which has a version number. I want to read the version number from this code so I can compare it with other code I am using. I have code done below but cannot get it working, can anyone see the problem?

print results

    r = re.compile(r'(version\s*\s*)(\S+)') 

    for l in results: 
        m1 = r.match(l) 
        if m1: 
            ID=map(int,m1.group(2).split("."))  
            l = r.sub(r'\g<1>' + '.'.join(['%s' % (v) for v in ID]), l)
            print ID

the results variable is:

Name Info Type Call version 1.0.40.437 Fri Oct  2 10:54:35 BST 2009

I have it done this way as I need the numbers in the ID separated into groups as I need to compare the 3rd number in the ID to the third number in the ID in another file.

The below answers are useful, but the way I had it would read a file and take all the numbers out and put them into a list so all I would have to do is compare the two numbers of the list. Sorry if the question was not clear but I don’t want the version number to be a string.

Okay I made a couple of changes to the code that was answered below. The code is as follows:

    version = re.compile('version\s+([\d.]+)\s+') 
    ID = version.search(results) 
    if ID: 
        value = ID.group(1).split('.')[2]

    self.assertEqual(BUILD_ID[2], int(value))

This does not create the list that I wanted but it allows me to compare the 2 values.

Thanks for all the help.

Answer 1

Why regexp? I should use split(‘ ‘) and use value next to ‘version’, or simplier:

print results.split(' ')[5]

If you must use regexp then try:

rx = re.compile('version\s+([\d.]+)\s+')
rxx = rx.search(results)
if rxx:
    print rxx.group(1)