Question

I have a table similar to the following.

<table class="schedule-table" cellspacing="1" border="0" style="width:100%;">  
  <tr class="DataRow" id="DataRow_1">  
    <td class="resource" style="display:none;">8</td>  
    <td class="resource">John Smith</td>  
    <td class="resource">blah blah blah</td>  
    <td class="resource">blah blah blah</td>  
    <td class="resource">blah blah blah</td>  
    <td class="resource">blah blah blah</td>  
  </tr>   
  <tr class="DataRow" id="DataRow_2">       
    <td class="resource" style="display:none;">9</td>  
    <td class="resource">Huck Fin</td>  
    <td class="resource">blah blah blah</td>  
    <td class="resource">blah blah blah</td>  
    <td class="resource">blah blah blah</td>  
    <td class="resource">blah blah blah</td>  
  </tr>   
  <tr class="DataRow" id="DataRow_3">  
    <td class="resource" style="display:none;">10</td>  
    <td class="resource">Tom Sawyer</td>  
    <td class="resource">blah blah blah</td>  
    <td class="resource">blah blah blah</td>  
    <td class="resource">blah blah blah</td>  
    <td class="resource">blah blah blah</td>  
  </tr>   
</table>

I’d like to select #DataRow_2 and replace the 4th and 5th cells with :

var newTd = <td class="newclass" colspan="2">Stuff for cell that should span two cells</td>

How can I accomplish this?

Answer 1

This should get you started:

$(document).ready(function(){
   var $row = $("#DataRow_2").find(".resource");
   $($row[4]).remove();
   $($row[3]).replaceWith($("<td class='newclass' colspan='2'>Stuff for cell</td>"));
});

I assume you have a broader use case so you’ll want to make a function and pass in the cells to remove, replace, etc.

You can play with the JSfiddle here:http://jsfiddle.net/UV2Ce/