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Home/ Questions/Q 7751607
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T11:35:32+00:00 2026-06-01T11:35:32+00:00

I have a view page in Yii. It is cached with page cache. Now,

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I have a “view” page in Yii.
It is cached with page cache.
Now, I want to insert some dynamic content:

$this->renderDynamic('renderPartial','view_name'); 

The rendered view looks like this:

<?php some code ?>  
<div>...some html...</div>

The code works fine, but there is this error:

<###dynamic-0###>

So I understand the html is being echoed instead of returned.
I try to pass the return=true to the renderPartial function.
What is the right syntax to do it?

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  1. Editorial Team
    Editorial Team
    2026-06-01T11:35:33+00:00Added an answer on June 1, 2026 at 11:35 am

    More info: http://www.yiiframework.com/doc/api/1.1/CController#renderDynamic-detail

    1. Cached view file:

      $this->renderDynamic('dynamicTest');
      
    2. Controller file (callback function):

      public function dynamicTest()
      {
          return $this->renderPartial('dynamicTest', null, true);
      }
      
    3. Dynamic view file:

      echo 'dynamicTest_' . time();
      

    I think that You forgot to add return in callback function (step 2).

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