Question

I have a xml that has so many elements and most of that contain attributes.. for some of the attributes values are same so I need to group them and generate diff xml.
I/p Ex:

<TestNode>
 <ABC1 value="10.7" format="$" />
 <ABC2 value="10.5" format="$" />
 <ABC3 value="20" format="Rs" />
 <ABC4 value="50" format="Rs" />
 <ABC5 value="10.5" format="$" />
</TestNode>

I need to group the rows by format. Note: Format is not fixed… it may grow …
O/P Ex:

is it possible to get ? Thanks in advance…

Answer 1

In XSLT 2.0 you should be able to do it with <xsl:for-each-group>, current-grouping-key() and current-group()

Example:

<xsl:for-each-group 
    select="TestNode/*"
    group-by="@format"
>
    <group format="{current-grouping-key()}">
        <xsl:for-each select="current-group()">
            <xsl:copy-of select="."/>
        </xsl:for-each>
    </group>
</xsl:for-each-group>

See: http://www.w3.org/TR/xslt20/#grouping