Question

I have an API (from third party java library) that looks like:

    public List<?> getByXPath(String xpathExpr)

defined on a class called DomNode

I try this in scala function:

1: def removeChild(node: DomNode, xpath: String) {
2:               val lst: List[?] =  node.getByXPath(xpath)
3:      val child: DomNode = lst(0)
4:                child.getParentNode().removeChild(child)
    }

but it does not compile in scala. I get error in line 2.

As per the answers I modified it and now it is:

1: def removeChild(node: DomNode, xpath: String) {
2:            val lst = node.getByXPath(xpath)
3:            val child = lst(0).asInstanceOf[DomNode]            
4:            child.getParentNode().removeChild(child)
    }

Now I get error on line 3: lst of type java.util.List[?0] does not take parameters

I also tried val lst: List[_] = node.getByXPath(xpath) but this gives me error right on this same line:

type mismatch;
 found : java.util.List[?0] where type ?0
 required: scala.List[_]

So I am still stuck.

Answer 1

Re your error on line 3: remember that it is a Java list, not a Scala list, so try

val child = lst.get(0).asInstanceOf[DomNode]