Question

I have an array of values, all strings. There are also 2 “marker” entries in the array, that signify what the values that follow are. Basically it’s set up like so:

$array['1','2','3','A','5','6','7','B','8','9']

I need to retrieve the array indices after A, but before B. So, in this example, the indices of 5, 6, and 7.

I was thinking about doing this with a forloop and some iterative if statements.. But I can’t seem to figure it out. Any help is much appreciated 🙂

EDIT: also worth noting that A and B are not always at the same position in the array; some users will have more data between A and B than others, some won’t have A and B at all. But if A is present, I need to get the values following it. If A and B are present they will also always have the same value (A and B).

EDIT2: This is what I’m currently trying as per PeeHaa’s suggestions. A is “registered:current” and B is “registered:next”. In his testing he is getting the value that comes after A but before B, however in my tests I am only getting the value of A (“registered:current”). It just outputs “registered:current” instead of the value that exists between the 2 markers.

function getValuesBetweenMarkers($theArray, $startMarker = 'registered:current', $endMarker = 'registered:next')
{
    $offset = array_search($startMarker, $theArray) + 1;
    $length = array_search($endMarker, $theArray) - $offset;

    return array_slice($theArray, $offset, $length, true);
}

Answer 1

I think this should work:

$result = array();
$start = "A";
$stop = "B";
$push = false;
foreach($array as $value) {
    if ($value == $start) {
         $push = true;
    } else if ($value == $stop) {
        break;
    }
    if ($push) {
        $result[] = $value;
    }
}