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Home/ Questions/Q 8192061
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T04:04:43+00:00 2026-06-07T04:04:43+00:00

I have an interface like so: public interface MyInterface<E extends Something1> { public void

  • 0

I have an interface like so:

public interface MyInterface<E extends Something1> {
    public void meth1(MyClass1<E> x);
}

and I have a subclass whose superclass implements the above interface:

public class MyClass2<E extends Something1> extends Superclass{

    public MyClass2(){

    }

    public void meth1(MyClass1 x) {
        // TODO Auto-generated method stub

    }
}

superclass:

public abstract class Superclass<E extends Something1> implements MyInterface{
    MyClass1<E> x;
    protected E y;

    public Superclass(){

    }
}

MyClass1:

public abstract class Myclass1<E extends Something1> {

    public Myclass1(){

    }
}

the problem is that the parameter for meth1() is supposed to be generic. If I do MyClass1 it doesn’t like it and the only way I can get it to compile is by leaving out generic parameters- which feels wrong.

What’s going wrong?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-07T04:04:45+00:00Added an answer on June 7, 2026 at 4:04 am

    Here are your classes now parameterised appropriately:

    class Something1 { }
    
    public interface MyInterface<E extends Something1> {
        public void meth1(MyClass1<E> x);
    }
    
    // and I have a subclass whose superclass implements the above interface:
    public class MyClass2<E extends Something1>
        extends Superclass<E> {
    
        public MyClass2() { }
    
        public void meth1(MyClass1<E> x) { }
    }
    
    // superclass:
    public abstract class Superclass<E extends Something1> implements
            MyInterface<E> {
        MyClass1<E> x;
        protected E y;
    
        public Superclass() { }
    }
    
    // MyClass1:
    public abstract class MyClass1<E extends Something1> {
    
        public MyClass1() {
    
        }
    }
    
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