Question

I have been messing with this for while now and I hope you guys can help.
So I have a XSL variable like

<xsl:variable name="blah" select="'texttexttext texttexttexttext Note:texttexttexttext'" />

What I’m trying to do is first search for “Note:” in $blah. If it is found, add a line break before it like 
 . So the output will be like

blah-> "'texttexttext texttexttexttext 
Note:texttexttexttext'"

I’m able to search for the term using the usual contains function like:

<xsl:if test="(contains($blah,'Note:'))">true</xsl:if>

but I’m confused on getting replace/insert of line break

Answer 1

XSLT 2.0 comes with some nice regex functions.

By using the replace function as here :

replace($blah, "(.*)(Note:.*)", "$1
$2")

You shall get the desired result. So basically, I am catching all before and after Note: and I am just putting your line-break in between at the result.