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Home/ Questions/Q 8371281
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T14:07:32+00:00 2026-06-09T14:07:32+00:00

I have code like the following: function test(obj) { if(//some conditon) { obj.onload(); }else{

  • 0

I have code like the following:

function test(obj) {

    if(//some conditon) {
        obj.onload();
    }else{
        obj.onerror();
    }
}


for(var i=0;i<4;i++){   

    test({
        onload:function(e){          
            //some code to run
        },
        onerror:function(e){
            break;
        }


    });
}

The gist is the test() function is a function to make an XHR request (it is actually an API of the Appcelerator Titanium platform so I have no control over it) and I’m looping something to call the test function. I need to break the loop on the onerror function, but I get an error saying the break is not inside a loop or switch statement. How can I rewrite this?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T14:07:33+00:00Added an answer on June 9, 2026 at 2:07 pm

    If your code sample does represent some actual code (i.e. all the processing is done in the same event loop tick), you may do the following:

    function test(obj) {
    
        if (some_condition) {
            return obj.onload();
        } else {
            return obj.onerror();
        }
    }
    
    var result;
    for(var i=0; i<4; i++){   
    
        result = test({
            onload:function(e){          
                //some code to run
                return true;
            },
            onerror:function(e){
                return false;
            }
    
    
        });
    
        if (!result) {
            break;
        }
    }
    

    Otherwise, if there is something asynchronous done, you have to call test sequentially, and not in parallel. For example,

    function test(obj) {
        doSomeAjaxRequest(arguments, function (err, result) {
            if (some_condition) {
                obj.onload();
            } else {
                obj.onerror();
            }
        });
    }
    
    var f = function (i) {
        if (i >= 4) return;
        test({
            onload:function(e){          
                //some code to run
                f(i+1);
            },
            onerror:function(e){
                break;
            }
        });
    }
    
    f(0);
    
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