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Home/ Questions/Q 6007145
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T01:38:23+00:00 2026-05-23T01:38:23+00:00

I have come across this situation. In the hash1 first column is the key

  • 0

I have come across this situation.
In the hash1 first column is the key and the rest is datavalue, similarly in the hash2.

So what I m trying to do is I want to compare these two hashes and

if a record is in hash2 and not in hash1 then its an add

if a record is in hash1 and not in hash2 then its a drop.

I want both adds and drops list.I want to compare with hash1 with hash2 or vice-versa and get the adds and drops without using CPAN modules.

Hash1

739574562   Dexheimer       James           University Libraries            Coord Fast Cataloging   jdexheim
766631088   Rolls           Erlinda         University Libraries            Prof-Support-Waldo Lib  rolls
204707142   Reish           Joseph          University Libraries            Dean University
127759797   PRIEST          DANIEL          University Libraries            Temporary Student-Non e 
133708988   BRODHEAD        MATTHEW         University Libraries            Temporary Student-Non e 
......
......
......

Hash2

381753669   BRAMAN                  MELISSA             University Libraries            Temporary Non-Exempt    
127759797   PRIEST                  DANIEL              University Libraries            Temporary Student-Non e 
133708988   BRODHEAD                MATTHEW             University Libraries            Temporary Student-Non e 
204707142   Reish                   Joseph              University Libraries            Dean University
......
......
......

In this case output should be like this:

Adds  : BRAMAN          MELISSA         University Libraries            Temporary Non-Exempt 

Drops : Dexheimer       James           University Libraries            Coord Fast Cataloging   jdexheim
        Rolls           Erlinda         University Libraries            Prof-Support-Waldo Lib  rolls
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T01:38:23+00:00Added an answer on May 23, 2026 at 1:38 am
    for (keys(%h1)) {
       if (!exists($h2{$_})) {
          print("Dropped $_\n");
       }
    }
    
    for (keys(%h2)) {
       if (!exists($h1{$_})) {
          print("Added $_\n");
       }
    }
    

    Tweak the output to your liking.

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