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Home/ Questions/Q 8169795
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T20:57:36+00:00 2026-06-06T20:57:36+00:00

I have form with fields: public VyjimkyForm(final Parametry parametry) { super(vyjimkyForm, new CompoundPropertyModel<Parametry>(parametry)); setOutputMarkupId(true);

  • 0

I have form with fields:

    public VyjimkyForm(final Parametry parametry) {
        super("vyjimkyForm", new CompoundPropertyModel<Parametry>(parametry));
        setOutputMarkupId(true);
        add(new DropDownChoice<String>("datumy", new Datumy())).add(
                new AjaxFormComponentUpdatingBehavior("onchange") {

                    private static final long serialVersionUID = 1L;

                    @Override
                    protected void onUpdate(AjaxRequestTarget target) {
                       ...
                    }
                });
}

this code thrown exception:

Behavior cz.isvs.reg.rob.monitor.web.VyjimkyPage$VyjimkyForm$1 can only be added to an instance of a FormComponent. WHy I cant add this behavior ? this drop choice is in form

when I run this code this exception is thrown:

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T20:57:38+00:00Added an answer on June 6, 2026 at 8:57 pm

    You misplaced a closing bracket.

    add(new DropDownChoice<String>("datumy", new Datumy()).add(
        new AjaxFormComponentUpdatingBehavior("onchange") {
    
            private static final long serialVersionUID = 1L;
    
                @Override
                protected void onUpdate(AjaxRequestTarget target) {
                           ...
            }
        }));
    

    should do the trick.

    With your placement of the brackets you were trying to add the behaviour to the enclosing component.

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