Question

I have gotten the HTML of a webpage using Python, and I now want to find all of the .CSS files that are linked to in the header. I tried partitioning, as shown below, but I got the error “IndexError: string index out of range” upon running it and save each as its own variable (I know how to do this part).

sytle = src.partition(".css")
style = style[0].partition('<link href=')
print style[2]
c =1

I do no think that this is the right way to approach this, so would love some advice. Many thanks in advance. Here is a section of the kind of text I am needing to extract .CSS file(s) from.

    <meta name="viewport" content="width=device-width, initial-scale=1.0, minimum-scale=1.0" />

<!--[if gte IE 7]><!-->
<link href="/stylesheets/master.css?1342791430" media="screen, projection" rel="stylesheet" type="text/css" />

<link href="/stylesheets/adapt.css?1342791413" media="screen, projection" rel="stylesheet" type="text/css" />
<!-- <![endif]-->
<link href="/stylesheets/print.css?1342791421" media="print" rel="stylesheet" type="text/css" />
<link href="/apple-touch-icon-precomposed.png" rel="apple-touch-icon-precomposed" />
<link href="http://dribbble.com/shots/popular.rss" rel="alternate" title="RSS" type="application/rss+xml" />

Answer 1

You should use regular expression for this. Try the following:

/href="(.*\.css[^"]*)/g

EDIT

import re
matches = re.findall('href="(.*\.css[^"]*)', html)
print(matches)