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Home/ Questions/Q 8304505
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T17:51:58+00:00 2026-06-08T17:51:58+00:00

I have next function var hideAll = function() { // code return ///… };

  • 0

I have next function

  var hideAll = function() {
    // code  
    return ///...  
  };  

And I am using this function like callback in another function.
When I am using it like

function (params, hideAll) {}  

all working well, but when I am using

function (params, hideAll() ) {}    

all not working well!

So my question is, what is difference between hideAll and hideAll() function executions?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T17:52:00+00:00Added an answer on June 8, 2026 at 5:52 pm

    hideAll – this is a reference to the function
    hideAll() – this is execution of the function, its result

    function (params, hideAll) {} is a correct function definition,
    whereas function (params, hideAll() ) {} is not – you are unable to call another function in function definition.

    However you could still write the following valid code:

      var hideAll = function() {
        // code  
        return ///...  
      };  
    
      var functionWithCallback = function(callback){
          callback();
      }
      var closureReferringHideAll = function(){
          hideAll();
      }
    
      // The following two lines will do exactly the same in current context,
      // i.e. execute hideAll.
      functionWithCallback(hideAll);
      closureReferringHideAll();
    
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