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Home/ Questions/Q 6007197
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T01:38:48+00:00 2026-05-23T01:38:48+00:00

I have: $(#option1).live(click, function(){ $(.active).removeClass(‘active’); $(this).addClass(‘active’); $(#main).load(option1.php, function(){ }); }); and the script inside

  • 0

I have:

$("#option1").live("click", function(){
    $(".active").removeClass('active');
    $(this).addClass('active');
    $("#main").load("option1.php", function(){
    });
});

and the script inside runs perfectly. However what I really need is to call only one section of the option1.php page, like this:

$("#option1").live("click", function(){
    $(".active").removeClass('active');
    $(this).addClass('active');
    $("#main").load("option1.php #container", function(){
    });
});

Bute then the script stops working, I’m assuming that is because I’m leaving out the head tags that contain the script. How can I make it run while loading only one section of the page? is it possible?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T01:38:49+00:00Added an answer on May 23, 2026 at 1:38 am

    It is a PHP script, you can easily send only a part of your page.
    After, to load that, you can use the $.ajax jquery object :

    function loadContainer()
    {
        var ajaxobject = $.ajax(
        {
            type:"POST",
            url:"option1.php",
            cache:false,
            async:true,
            global:false,
            dataType:"html",
            data:"part=container",
            timeout:10000,
            success:function(data)
            {
                $('#container').html(data);
            },
            error:function()
            {
                alert('Error; Unable to load option1.php');
            }
        });
        if(ajaxobject == undefined)
            alert('Ajax object creation failed');
    }
    

    On the PHP side, you just need to check if $_POST['part'] equals container.
    If yes, send only the part you want to send.

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