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Home/ Questions/Q 4325316
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T09:15:01+00:00 2026-05-21T09:15:01+00:00

I have problem using dict in python, I just end up with empty dictionary.

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I have problem using dict in python, I just end up with empty dictionary.

looks like I erase the data each itartion

this code suppose to generate a tests that include tests for each site.

thanks in advance

tests={}
for t in Test.objects.all():
    for s in Site.objects.all():
        site={}
        for sv in s.siteversions.all():
            siteversion=sv.version
            results=sv.results.filter(idTest=t)
            result=""
            if(results):
                result=results[0].result_test()
            site.update({sv.version:result})
        tests.update({t.name:site.copy()})
print tests

{u'load stuff': {u'X2': 'Success', u'X1': ''}}
{u'load stuff': {u'XP': 'Error'}}
{u'load stuff': {}}
{u'load stuff': {}, u'unload': {u'X2': 'Fail', u'X1': 'Error'}}
{u'load stuff': {}, u'unload': {u'XP': 'Success'}}
{u'load stuff': {}, u'unload': {}}

x2 and xp are versions

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-21T09:15:02+00:00Added an answer on May 21, 2026 at 9:15 am

    tests.update({t.name:site.copy()}) is executed for each site but with the same key: testname and somtimes you have sites witout test -> end up with empty dictionary.

    to fix this you need a strcture like the following:

    Test1 -> site1 -> test_results1
             site2 -> test_results2
             ...
    
    Test2 -> site1 -> test_results1
             site2 -> test_results2
             ...
    

    something like this:

    tests={}
    for t in Test.objects.all():
        sites={}
        for s in Site.objects.all():
            site_results={}
            for sv in s.siteversions.all():
                results=sv.results.filter(idTest=t)
                result = ''
                if(results):
                    result=results[0].result_test()
                site_results[sv.version] = result
        sites[s.name] = site_results
    tests[t.name] = sites
    
    print tests
    
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