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Home/ Questions/Q 8263619
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Editorial Team
  • 0
Editorial Team
Asked: June 8, 20262026-06-08T04:10:25+00:00 2026-06-08T04:10:25+00:00

i have setup some ajax, which i am just testing now, pretty much the

  • 0

i have setup some ajax, which i am just testing now, pretty much the idea behind it is to send some data from dropdown boxes to a php script, do some calculations and then return the result, it does it well and returns the result, but now rather than just sending back one result and outputting that, i want to send back multiple results and output them, i am able to send multiple data to the php script, so i am sure i can send multiple back.

Anyway it only sends the first result back and not the rest.

Here is the AJAX

 <script>
$("document").ready(function (){ 

    $(".add_extension").change(function(){


        var m = document.getElementById('meter_square');
        var meter_square = m.options[m.selectedIndex].value;

        var s = document.getElementById('story_height');
        var story_height = s.options[s.selectedIndex].value;

     $.ajax({
            type: "GET",
            url: "script.php",
            data: { meter_square: meter_square, story_height: story_height },
            dataType: "json",
            statusCode: {
                200: function (result, result2)
                {
                    $("#expected_gain").html(result.value);
                $("#house_price").html(result2.value2);
                }

            }
        });
})
});
</script>   

And here is the php script

    <?php 

$meter_square = $_GET["meter_square"];
$story_height = $_GET["story_height"];


$result = $meter_square + $story_height;
$result2 = $meter_square * $story_height;

echo json_encode(array("value" => $result, "value2" => $result2));

 ?>

You can see that i have already tried to give it a go from what i thought might work, if you need any other code or want me to remove the code i added which doesn’t work, then let me know.

Thanks for all and any help

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T04:10:27+00:00Added an answer on June 8, 2026 at 4:10 am

    You’re only going to receive one response object:

    function (response) {
        $("#expected_gain").html(response.value);
        $("#house_price").html(response.value2);
    }
    
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