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Home/ Questions/Q 8354029
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T09:26:00+00:00 2026-06-09T09:26:00+00:00

I have the 3 Following Tables: objects: ObjectID ObjectDescription 1 first 2 second attributes:

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I have the 3 Following Tables:

objects:

ObjectID ObjectDescription
1        "first"
2        "second"

attributes:

AttributeID AttributeDescription
1           "att1"
2           "att2"
3           "att3"
4           "att4"

attributelink:

AttributeID ObjectID
1           1
2           1
4           1

Now my question: I want now have some attributes selected and want to know, which Object has all my selected Attributes. I’ve tried the following:

SELECT * FROM `objects` 
    INNER JOIN `attributelink` 
         ON `objects`.`ObjectID` = `attributelink`.`ObjectID`
    WHERE `attributelink`.`AttributeID` =1 AND `attributelink`.`AttributeID` =2  
GROUP BY `objects`.`ObjectID` 

That obviously doesn’t work, because one row can’t have 2 AttributeIDs, but how can I archieve this?

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  1. Editorial Team
    Editorial Team
    2026-06-09T09:26:02+00:00Added an answer on June 9, 2026 at 9:26 am

    You have to join on the attributelink table once for each selected attribute you want to check for:

    SELECT o.ObjectID
    FROM objects o
    INNER JOIN attributelink a1 ON o.ObjectID = a1.ObjectID AND a1.AttributeID = 1
    INNER JOIN attributelink a2 ON o.ObjectID = a2.ObjectID AND a2.AttributeID = 2
    GROUP BY o.ObjectID
    

    Your test data doesn’t show a whole lot about whether it works or not, but FWIW, here’s the sqlfiddle.


    Another way to do it is to use COUNT DISTINCT with HAVING and GROUP BY (sqlfiddle):

    SELECT o.ObjectID
    FROM objects o
    INNER JOIN attributelink a ON o.ObjectID = a.ObjectID
    WHERE a.AttributeID IN (1,2) --here you filter the rows on the attributes to test
    GROUP BY o.ObjectID
    HAVING COUNT(DISTINCT(a.AttributeID)) = 2 --# of attributes, means "having ALL"
    
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