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Home/ Questions/Q 8321047
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T22:52:59+00:00 2026-06-08T22:52:59+00:00

I have the follow Models (an example, not really one): class ModelB(models.Model): name =

  • 0

I have the follow Models (an example, not really one):

class ModelB(models.Model):
  name = models.CharField(max_length=50)

  def __str__(self):
    return self.name

class ModelA(models.Model):
  code = models.CharField(max_length=50, unique=True, help_text="Code unique")
  foreignkey = models.ForeignKey(ModelB, unique=True)

And in my admin.py I have:

class ModelBAdmin(admin.ModelAdmin):
  list_display = ('name',)

class ModelAAdmin(admin.ModelAdmin):
  list_display = ('code', 'foreignkey')

admin.site.register(ModelA, ModelAAdmin)
admin.site.register(ModelB, ModelBAdmin)

I would make something similar to:

class ModelBAdmin(admin.ModelAdmin):
   list_display = ('name', 'code')

The code must be the code-relation from ModelA-code. How I can make this?

P.D.: Sorry for my english…

Thx a lot,
Antonio.

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  1. Editorial Team
    Editorial Team
    2026-06-08T22:53:01+00:00Added an answer on June 8, 2026 at 10:53 pm

    You can define a custom item in list_display this way:

    class ModelBAdmin(admin.ModelAdmin):
    
        def modelA_Codes(self, inst):
            return ','.join([b.code for b in inst.modela_set.all()])
    
        list_display = ('name', 'modelA_Codes')
    

    Since one modelB can be attached to multiple modelA items, you probably need to return a list of the applicable codes for the specified ModelB.

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