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Home/ Questions/Q 8306427
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T18:19:44+00:00 2026-06-08T18:19:44+00:00

I have the following base class : template <template<class Type> class T2> class FundamentalClass

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I have the following base class :

template <template<class Type> class T2>
class FundamentalClass {
    typename T2<double> *_compose1;
    typename T2<int> *_compose2;

protected:
    FundamentalClass(); // Insert constructors here.

    template<class Strategy>
    T2<typename Strategy::Type> *Construct(void);

public:
    template <class Strategy>
    T2<typename Strategy::Type> *GetComposedObject(void);

};

with

template< template<class Type> class T2>
template<>
T2<double> *FundamentalClass<T2<double> >::GetComposedObject<DoubleStrategy>(void) {
    if( NULL == _compose1) {
        _compose1 = Construct<DoubleStrategy>(void);
    }
    return _compose1;
}

And other specializations for each composed object.

But, i need construct to be implemented by the derived class. Without templates, Construct whould be virtual. How can i achieve this goal ?

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  1. Editorial Team
    Editorial Team
    2026-06-08T18:19:45+00:00Added an answer on June 8, 2026 at 6:19 pm

    You can do this with compile-time polymorphism, via the Curiously Recurring Template Pattern (CRTP):

    template <template<class Type> class T2, class Derived>
    class FundamentalClass {
        ...
    
        template<class Strategy>
        T2<typename Strategy::Type> *Construct() {
            return static_cast<Derived *>(this)->DoConstruct<Strategy>();
        }
    

    And in Derived, write:

    template <template<class Type> class T2>
    class Derived: public FundamentalClass<T2, Derived<T2> >
    {
    public:
        template<class Strategy>
        T2<typename Strategy::Type> *DoConstruct() {
            ...
        }
    
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