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Home/ Questions/Q 638653
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T20:45:22+00:00 2026-05-13T20:45:22+00:00

I have the following code: Socket clientSocket = null; try { clientSocket = serverSocket.accept();

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I have the following code:

Socket clientSocket = null;
try {
   clientSocket = serverSocket.accept();
} catch (IOException e) {
   System.err.println("Accept failed.");
   System.exit(1);
}

The code is taken from a java.sun.com.

I have several questions concerning the above given short part of the code.

  1. Why do we want to catch an IOException. I though that IOException is something that can happen when we use input-output methods (not networking methods).

  2. What is the difference between the “System.err.println” and “System.println”?

  3. In the catch statement we have “e”. What for? Do we use it latter?

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  1. Editorial Team
    Editorial Team
    2026-05-13T20:45:22+00:00Added an answer on May 13, 2026 at 8:45 pm

    1: Why do we want to catch an IOException. I though that IOException is something that can happen when we use input-output methods (not networking methods).

    Networking is also input/output. Byte streams through a socket.

    2: What is the difference between the “System.err.println” and “System.println”?

    The first writes to stderr, the second doesn’t exist.

    3: In the catch statement we have “e”. What for? Do we use it latter?

    To have a reference to the exception so that you can if necessary log or rethrow it.

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