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Home/ Questions/Q 1103651
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T01:22:18+00:00 2026-05-17T01:22:18+00:00

I have the following code, using Django ORM routes =Routes.objects.filter(scheduleid=schedule.id).only(‘externalid’) t_list = [(route.externalid, route.vehicle.name)

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I have the following code, using Django ORM

    routes =Routes.objects.filter(scheduleid=schedule.id).only('externalid')
    t_list = [(route.externalid, route.vehicle.name) for route in routes])

and it is very slow, because the vehicle objects are huge (dozens of fields, and I cannot change that, it is coming from a legacy database). A lot of time is devoted to create the Vehicle objects, while I only need the name field of this object.

Is there a more efficient way to obtain t_list ? I am looking for something like only() for accessing objects through a foreign key.

EDIT :
the solution is the following :

routes=Routes.objects.filter(scheduleid=schedule.id).select_related("vehicle")
routes= routes.only('externalid','vehicle__name')  

Does there exist something similar ?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-17T01:22:19+00:00Added an answer on May 17, 2026 at 1:22 am

    You should be able to do this, I think. Warning: not tested Tested using local models. Generated query looked good.

    routes = Routes.objects.select_related('vehicle').filter(**conditions).only(
                'externalid', 'vehicle__name')
    

    For this to work there should be a vehicle foreign key field declared in Routes model. This is ’cause select_related() only follows forward relationships.

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