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Home/ Questions/Q 8327717
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T01:12:33+00:00 2026-06-09T01:12:33+00:00

I have the following data in my table column information array( ‘Email: Customer One

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I have the following data in my table column information

array( 'Email: Customer One <customer1@yahoo.com>. By employee: james@company.com.',
    'By employee: james@company.com. Department Head: Nickolas Jim.',
    'Email: Customer One <customer2@yahoo.com>. Status: currently employees.',
    'Email: Customer One <customer3@yahoo.com>. By employee: Mirza@company.com.'
)

Etc, etc

I have a need to get the ‘By employee’ from the array. In other words I am in a need of regex solution

ED. I just need the By employee if present..nothing else
So in above example I will have

By employee: james@company.com
By employee: james@company.com
By employee: Mirza@company.com
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T01:12:35+00:00Added an answer on June 9, 2026 at 1:12 am

    I have tested following sample code in php 5.4.5:

        <?php
    $foo = array( 'Email: Customer One <customer1@yahoo.com>. By employee: james@company.com.',
                  'By employee: james@company.com. Department Head: Nickolas Jim.',
                  'Email: Customer One <customer2@yahoo.com>. Status: currently employees.',
                  'Email: Customer One <customer3@yahoo.com>. By employee: Mirza@company.com.'
                );
    
    for($i = 0; $i < count($foo); ++$i){
        if(0 >= preg_match('/\bBy employee: ([-\w._]+@[-\w]+(?:\.[-\w]+)*\.\w{2,4})\b/', $foo[$i], $matches))
            continue;  
    
        echo $matches[0] . "\n";
        echo $matches[1] . "\n";
        echo "\n";  
    }            
    
    ?>
    

    output:

            By employee: james@company.com
    james@company.com
    
    By employee: james@company.com
    james@company.com
    
    By employee: Mirza@company.com
    Mirza@company.com
    
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