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Home/ Questions/Q 8162505
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T18:44:01+00:00 2026-06-06T18:44:01+00:00

I have the following function private Integer calculateWeeklyValue(String p_Value, String Frequency) { if (p_Value.length()

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I have the following function

private Integer calculateWeeklyValue(String p_Value, String Frequency) {

    if (p_Value.length() == 0)
        p_Value = "0";
    Integer Value = Integer.parseInt(p_Value);
    if (Frequency.equals("W"))
        return (Integer)Value;
    else if (Frequency.equals("F"))
        return (Integer)((Value / 2));
    else if (Frequency.equals("M"))
        return (Integer)((Value * 12) / 52);
    else if (Frequency.equals("Q"))
        return (Integer)((Value * 4) / 52);
    else if (Frequency.equals("Y"))
        return (Integer)(Value / 52);
    else
        return 0;

}

It always returns the calue of the variable “Value” even though it matches the different cases.
for eg. it goes to “return (Integer)((Value * 12) / 52);” but then goes to return 0 and returns “Value”. Might be a stupid question but stuck on this.

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  1. Editorial Team
    Editorial Team
    2026-06-06T18:44:04+00:00Added an answer on June 6, 2026 at 6:44 pm

    Use int.and check your Value is always 0.

     int Value = Integer.parseInt(p_Value); and return type also `int`.
    
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