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Home/ Questions/Q 4082142
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T18:09:02+00:00 2026-05-20T18:09:02+00:00

I have the following knockout.js code I’ve got the following: var itemLine = function()

  • 0

I have the following knockout.js code

I’ve got the following:

var itemLine = function() {
    this.itemId = ko.observable();
    this.itemType = ko.observable();
    ///this.otherFields = = ko.observable();....
};

var itemSet = function () {
    this.items = ko.observableArray(_.map(initialData, function (item) {
        var newItem = new itemLine();
        newItem.itemId(item.itemId);
        newItem.itemType(item.itemType);
        return newItem;
    }));

    this.current = new itemLine();

    // works, but it req duplication of all my fields
    this.add = function () {
        var newItem = new itemLine();
        newItem.itemId(this.current.itemId());
        newItem.itemType(this.current.itemType());

        this.items.push(newItem);
        this.current.itemerId("");
        this.current.itemType("");
    };

    // doesn't work
     this.add = function () {
        this.items.push(this.current);
        this.current = new interviewLine(); // bindings are lost
    };

What is wrong in the second add implementation? What’s the correct way of doing this?

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  1. Editorial Team
    Editorial Team
    2026-05-20T18:09:03+00:00Added an answer on May 20, 2026 at 6:09 pm

    Currently, in your second add you are not actually updating the observables, just replacing them with new ones.

    What I would do is make this.current an observable. Then in your second version of add you will set current to the new value like you would set any observable.

    So, in your itemSet contructor you would initialize this.current like:

    this.current = ko.observable(new itemLine());
    

    Then, in your second add function, set this.current like:

    this.current(new interviewLine());
    

    Something like this: http://jsfiddle.net/rniemeyer/j72NU/

    Is this close to what you are trying to do?

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