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Home/ Questions/Q 4545264
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T15:47:20+00:00 2026-05-21T15:47:20+00:00

I have the following tree 1 2 3 4 5 6 7 8 9

  • 0

I have the following tree

     1
    2 3
   4 5 6
  7 8 9 0

Now i want to walk through all possible paths trough the tree. It is always possible to move to adjacent numbers from the row below. For example

1 2 4 7 or 1 2 5 8

Any hints what is the best way to do that? I’m looking for a general hint, but in my implementation I have an ArrayList for each row.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-21T15:47:20+00:00Added an answer on May 21, 2026 at 3:47 pm

    I suspect using recursion is the simplest way.

    something like

    public static void visit(List<List<Integer>> tree, Visitor<List<Integer>> visitor) {
        visit0(tree, visitor, Collections.<Integer>emptyList());
    }
    
    private static void visit0(List<List<Integer>> tree, 
                               Visitor<List<Integer>> visitor, List<Integer> list) {
        if (tree.isEmpty()) {
           visitor.onList(list);
           return;
        }
    
        List<List<Integer>> tree2 = tree.subList(1, tree.size() - 1);
        List<Integer> ints = new ArrayList<Integer>(list);
        ints.add(0); // dummy entry.
        for(int n: tree.get(0)) {
            ints.set(ints.size()-1, n);
            visit0(tree2, visitor, ints);
        }
    }
    
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