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Home/ Questions/Q 1079419
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Editorial Team
  • 0
Editorial Team
Asked: May 16, 20262026-05-16T21:52:00+00:00 2026-05-16T21:52:00+00:00

I have this code: def random_answerlist(self): self.li = [] self.winning_button = random.randint(0, 3) i

  • 0

I have this code:

def random_answerlist(self):
    self.li = []
    self.winning_button = random.randint(0, 3)
    i = 0
    while i < 20 and len(self.li) is not 4:
        if i == self.winning_button:
            self.li.append(self.flags[self.current_flag][0])
        else:
            new_value = self.random_value()
            if self.flags[new_value][0] not in self.li:
                self.li.append(self.flags[new_value][0])
        i += 1
    return self.li

The only problem with it is that the first if-case may happen several times which should be impossible. I have searched for a good explanation to this and I can’t find any.

Oh, I know the code isn’t the best. But I’m kind of new to python (just a month or so) and thought this might work, but it didn’t!

Do you guys know why? =)

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  1. Editorial Team
    Editorial Team
    2026-05-16T21:52:01+00:00Added an answer on May 16, 2026 at 9:52 pm

    One glaring problem is the usage of is not for a value comparision against len(self.li). The tests is not and != are not the same. is tests for identity (are these references to the same object?), != tests for equality (do these objects have the same value?).

    Change your while to:

    while i < 20 and len(self.li) != 4:
    

    Does that address the issue?

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