Question

I have this code in Python:

conn = sqlite3.connect("people.db")
cursor = conn.cursor()

sql = 'create table if not exists people (id integer, name VARCHAR(255))'
cursor.execute(sql)
conn.commit()

sql = 'insert into people VALUES (3, "test")'
cursor.execute(sql)
conn.commit()   

sql = 'insert into people VALUES (5, "test")'
cursor.execute(sql)
conn.commit()  

print 'Printing all inserted'
cursor.execute("select * from people")
for row in cursor.fetchall():
    print row

cursor.close()
conn.close()

But seems is never saving to the database, there is always the same elements on the db as if it was not saving anything.

On the other side If I try to access the db file via sqlite it I got this error:

Unable to open database "people.db": file is encrypted or is not a database

I found on some other answers to use conn.commit instead of conn.commit() but is not changing the results.

Any idea?

Answer 1

This seems to work alright for me (“In database” increases on each run):

import random, sqlite3

conn = sqlite3.connect("people.db")
cursor = conn.cursor()

sql = 'create table if not exists people (id integer, name VARCHAR(255))'
cursor.execute(sql)

for x in xrange(5):
    cursor.execute('insert into people VALUES (?, "test")', (random.randint(1, 10000),))
conn.commit()

cursor.execute("select count(*) from people")
print "In database:", cursor.fetchone()[0]