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Home/ Questions/Q 8367325
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T13:07:42+00:00 2026-06-09T13:07:42+00:00

I have this code: int main() { char ch[15]; cout<<strlen(ch)<<endl; //7 cout<<sizeof(ch)<<endl; //15 return

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I have this code:

int main()
{
    char ch[15];
    cout<<strlen(ch)<<endl; //7
    cout<<sizeof(ch)<<endl; //15
    return 0;
}

Why does strlen(ch) give different result even if it is empty char array?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T13:07:43+00:00Added an answer on June 9, 2026 at 1:07 pm

    ch is a local variable and local variables are not initialized. So your assumption that it is an empty string is not correct. Its filled with junk. It was just a co-incidence that a \0 character was found after 7 junk characters and hence strlen returned 7.

    You can do something like these to ensure an empty string-

    char ch[15]={0};
    ch[0]='\0`;
    strcpy(ch,"");
    

    Here’s a similar thread for more reading

    Variable initialization in C++

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