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Home/ Questions/Q 5984699
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T22:24:59+00:00 2026-05-22T22:24:59+00:00

I have this code which works. $(document).ready(function(){ $(‘form’).live(‘submit’, function(){ // have to do it

  • 0

I have this code which works.

$(document).ready(function(){
  $('form').live('submit', function(){

     // have to do it like this to simulate my problem
     var aform = $(this);

     var dat = { "TITLE" : "55h5", "OWNER" : "fff" };
     $('#template').tmpl(dat).prependTo('#content');

    return false;

  });
});

But what I would like is to take the values from aform and insert them directly into

$('#template').tmpl(  HERE   ).prependTo('#content');

The data from the form have do accessed through aform to simulate my problem. Can this be done?

Here is the problem illustrated

http://jsfiddle.net/HYLYq/

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T22:25:00+00:00Added an answer on May 22, 2026 at 10:25 pm

    You could use .serializeArray(), and then loop over it to create the right data structure:

    var data = {},
        values = $(this).serializeArray();
    
    for(var i = values.length; i--;) {
        data[values[i].name] = values[i].value;
    }
    

    You could do the same with plain JavaScript (is probably faster):

    var elements = $(this)[0].elements,
        data = {};
    
    for(var i = elements.length; i--;) {
        data[values[i].name] = values[i].value;
    }
    
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