Question

I have this directory structure:

$ ls -F
analyze/
data.pl
input.pl
logminer.txt
logSearch.pl
readFormat.pl
Version Notes.txt
datadump.pl
format/
logminer.pl
logs/
properties.txt
unzip.exe

I run:

perl -e 'if (!(-d analyze)){ print "poo\n"}'

and it prints poo.

What is missing here? I have done tests like this earlier and it would correctly identify that the directory exists. Why not this directory?

Answer 1

perl -e 'if (!(-d "analyze")){ print "poo\n"}'
                  ^--     ^---

missing quotes?

edit: changed to double quotes – forgot this was for command-line perl