Question

I have this function that takes a pointer of an array (in order to modify it from within the function)

int func_test(char *arr[]){
    return 0;
}

int main(){
  char var[3];
  func_test(&var);

  return 0;
}

When I try to compile this I get :

passing argument 1 of ‘func_test’ from incompatible pointer type

Why is this problem, and how I pass a pointer to that array in this case?

Answer 1

char * arr[] is not a pointer to an array; it is an array of pointers. Declarations in C are read first from the identifier towards the right, then from the identifier towards the left. So:

    char * arr[];
//         ^ arr is...
//            ^ an array of...
//       ^ pointers to...
//  ^ char