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Home/ Questions/Q 8319975
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T22:29:59+00:00 2026-06-08T22:29:59+00:00

I have this generic class public class BinTree<T> { T value; List<BinTree<? extends T>>

  • 0

I have this generic class

public class BinTree<T> {

    T value;

    List<BinTree<? extends T>> branch = new ArrayList<BinTree<? extends T>>();

    public BinTree(T v){ value  = v;}

    public void addBranch(BinTree<? extends T> tree){
        if(branch.size() == 2){
            System.out.println("You can only have two childs");
        }else{
            branch.add(tree);
        }
    }

    public BinTree<? extends T> getBranch(int n){ return branch.get(n);}


}

And its implementation here

public static void main(String[] args){
        BinTree<Number> firstBinTree = new BinTree<Number>(0);
        firstBinTree.addBranch(new BinTree<Integer>(5));
        firstBinTree.addBranch(new BinTree<Double>(6.5));

        Number o = firstBinTree.getBranch(0).value;
        firstBinTree.getBranch(0).addBranch(new BinTree<Integer>(6));

    }   

But this line

firstBinTree.getBranch(0).addBranch(new BinTree<Integer>(6));

Is not allowing me to add another BinTree of Type integer. why is that? I declared in my addBranch method that it can add any type as long that is ia subclass of Type(in this case number) it would be added in the list but how come I can’t ? isn’t Integer a sub class of Number?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T22:30:01+00:00Added an answer on June 8, 2026 at 10:30 pm

    It will not know if the

    <? extends T> 
    

    in getBranch and addBranch are the same i think. So to it will be

    <? extends ? extends T>
    
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