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Home/ Questions/Q 8312425
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T20:09:37+00:00 2026-06-08T20:09:37+00:00

I have this mutable array: myIntegers = [NSMutableArray array]; [myIntegers addObject:[NSNumber numberWithInteger:indexDelete – 1]];

  • 0

I have this mutable array:

myIntegers = [NSMutableArray array];

[myIntegers addObject:[NSNumber numberWithInteger:indexDelete - 1]];

NSLog (@"Array: %@", myIntegers);

If I execute the code twice, with indexDelete first being 1 and then 2, I get this result:

Array: (
1
)

and then:

Array: (
2
)

But I would like to store both numbers like this:

Array: (
1
2
)

Why is it not adding, but replacing the object??

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T20:09:38+00:00Added an answer on June 8, 2026 at 8:09 pm

    You’re creating a new empty array every time that code executes, on this line:

    myIntegers = [NSMutableArray array];
    

    Adding an object to an empty array always leads to there being one object in that array.

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