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Home/ Questions/Q 8293609
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T13:53:09+00:00 2026-06-08T13:53:09+00:00

I have this php code that grabs binary( blob ) data from the database

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I have this php code that grabs binary( blob ) data from the database and displays as an image in a browser. However, everything after this is ignored. Is there a way that I can also use text queries/forms/tables? Basic HTML elements on the same page?

Having a page that can only display a picture from the DB and nothing else is useless to me.

<?php
    $mysqli=mysqli_connect('localhost','root','','draftdb');
    if (!$mysqli)
    die("Can't connect to MySQL: ".mysqli_connect_error());
    $imageid= 1;
    $stmt = $mysqli->prepare("SELECT PICTURE_ID FROM display WHERE INDEX_ID =?"); 
    $stmt->bind_param("i", $imageid);
    $stmt->execute();
    $stmt->bind_result($image);
    $stmt->fetch();
    header("Content-Type: image/jpeg");
    echo $image; 
?>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-08T13:53:11+00:00Added an answer on June 8, 2026 at 1:53 pm

    No, you can only have one Content-Type per page.

    What you should do is simply create another page, that contains both an image (with src pointing to the code you showed) and the form you want to display, like this:

    <html>
        <body>
            <div>
                <img src="image.php" alt="image retreived from DB" />
            </div>
            <form>
                <input type="text" name="foo" />
                ...
            </form>
        </body>
    </html>
    
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