Question

I have this query, which I know doesn’t work, but I’ve left it as it is as pseudo-code to help explain what I’m doing. I’m trying to get “Booking” and “Sales” totals from a Booking table by day-of-the-week for the past week. Hence, Mon1B = Bookings for Monday and Mon1S = Sales for Monday.

SELECT  
   CASE WEEKDAY(b.created)
   WHEN 0 THEN (SELECT COUNT(uuid) as Mon1B, SUM(amount) as Mon1S)
   WHEN 1 THEN (SELECT COUNT(uuid) as Tue1B, SUM(amount) as Tue1S)
   WHEN 2 THEN (SELECT COUNT(uuid) as Wed1B, SUM(amount) as Wed1S)
   WHEN 3 THEN (SELECT COUNT(uuid) as Thu1B, SUM(amount) as Thu1S)
   WHEN 4 THEN (SELECT COUNT(uuid) as Wed1B, SUM(amount) as Wed1S)
   WHEN 5 THEN (SELECT COUNT(uuid) as Wed1B, SUM(amount) as Wed1S)
   WHEN 6 THEN (SELECT COUNT(uuid) as Wed1B, SUM(amount) as Wed1S)
END CASE
FROM Bookings b
WHERE b.created > '#week1Start#' and b.created <= '#week1End#'

How can something like this be done in MySQL?

Answer 1

Yes, but case can only return one value. You can do it like this:

SELECT sum(CASE when WEEKDAY(b.created) = 0 then 1 else 0 end) as Mon1b,
       sum(case when weekday(b.created) = 0 then amount else 0 end) as Mon1S,
       ...
FROM Bookings b
WHERE b.created > '#week1Start#' and b.created <= '#week1End#'

You might find it easier as 7 rows, though:

select WEEKDAY(b.created), count(*) as cnt, sum(amount) as amt
from Bookings b
WHERE b.created > '#week1Start#' and b.created <= '#week1End#'
group by WEEKDAY(b.created)
order by 1