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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T04:37:34+00:00 2026-05-24T04:37:34+00:00

I have this strange problem. When debugging, I have sometimetimes code looking like this

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I have this strange problem. When debugging, I have sometimetimes code looking like this

<?php
$var = 15;
die($var);

die() function works, but outputs nothing

However, this one works

<?php
$var = 15;
die($var."<-");

http://sandbox.phpcode.eu/g/81462.php

How is it possible? Did I miss something? or is it bug?

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  1. Editorial Team
    Editorial Team
    2026-05-24T04:37:35+00:00Added an answer on May 24, 2026 at 4:37 am

    See http://www.php.net/manual/en/function.exit.php (die() is equivalent to exit())

    If status is a string, this function prints the status just before exiting.

    If status is an integer, that value will be used as the exit status and not printed. Exit statuses should be in the range 0 to 254, the exit status 255 is reserved by PHP and shall not be used. The status 0 is used to terminate the program successfully.

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