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Home/ Questions/Q 8358807
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T10:55:22+00:00 2026-06-09T10:55:22+00:00

I have tried to re-implement the QTableWidget.cellActivated(row, number) using PyQt4, to catch the coordinates

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I have tried to re-implement the QTableWidget.cellActivated(row, number) using PyQt4, to catch the coordinates of the currently active cell. The sample below does not work as expected, the method is not activated when a cell is clicked. Have I done something wrong?

class DictionaryTable(QtGui.QTableWidget):

    def __init__(self, parent=None):
        QtGui.QTableWidget.__init__(self, parent)

    def cellActivated(self, row, column):
        print row, column 
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  1. Editorial Team
    Editorial Team
    2026-06-09T10:55:24+00:00Added an answer on June 9, 2026 at 10:55 am

    Looking at the docs, i see:

    void QTableWidget::cellActivated ( int row, int column ) [signal]

    This
    signal is emitted when the cell specified by row and column has been
    activated This function was introduced in Qt 4.1.

    This is a signal, not an event. So you don’t need to [re]implement cellActivated method (it’s not a method, it’s a class attribute of signal type). You need to connect to the signal:

    class DictionaryTable(QtGui.QTableWidget):
    
        def __init__(self, language_code, parent=None):
            QtGui.QTableWidget.__init__(self, parent)
            self.cellActivated.connect(self.handleCellActivated)
    
        def handleCellActivated(self, row, column):
            print row, column 
    
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