Question

I have Windows PC. My script should identify sequency number of the file passed in the command line in the folder, i.e.

myscript.py \\network-drive\files\Long-long.file.name.with.numbers.txt

Folder content is the following:

\\network-drive\files\
    folder1
    folder2
    file1
    file2
    Long.long.file.name.with.numbers.txt
    file3
    file4

My script should identify sequence number of the file given in the command line, i.e. should return 5 (folders are also to be counted; assumption is that files are sorted by their names).

Upd. I’ve stopped with the following:

import sys
import os.path

if sys.argv[1]: # regardless of this verification, exception happens if argument is not passed
    head, tail = os.path.split(sys.argv[1])
    print head
    print os.listdir(head)

The list returned by listdir doesn’t allow me to identify what is folder and what is file. So, I can not sort them properly.

Answer 1

It looks like something like this should work:

import os
import glob
import sys
import os.path as path

try:
    directory,file = path.split( sys.argv[1] )
    def sort_func(fname):
        """
        Russian directories , english directories, russian files then english files
        although, honestly I don't know how russian files will actually be sorted ...
        """
        fullname = path.join(directory,fname)
        isRussian = any(ord(x) > 127 for x in fullname)
        isDirectory = path.isdir(fullname)
        return ( not isDirectory, not isRussian, fullname)

    files = sorted( os.listdir(directory), key=sort_func)
    print ( files.index(file) + 1 )

except IndexError:
    print "oops, no commandline arguments"