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Home/ Questions/Q 8184027
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T01:21:37+00:00 2026-06-07T01:21:37+00:00

I just discovered set -u in bash and it helped me find several previously

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I just discovered set -u in bash and it helped me find several previously unseen bugs. But I also have a scenario where I need to test if a variable is defined before computing some default value. The best I have come up with for this is:

if [ "${variable-undefined}" == undefined ]; then
    variable="$(...)"
fi

which works (as long as the variable doesn’t have the string value undefined). I was wondering if there was a better way?

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  1. Editorial Team
    Editorial Team
    2026-06-07T01:21:39+00:00Added an answer on June 7, 2026 at 1:21 am

    What Doesn’t Work: Test for Zero-Length Strings

    You can test for undefined strings in a few ways. Using the standard test conditional looks like this:

    # Test for zero-length string.
    [ -z "$variable" ] || variable='foo'
    

    This will not work with set -u, however.

    What Works: Conditional Assignment

    Alternatively, you can use conditional assignment, which is a more Bash-like way to do this. For example:

    # Assign value if variable is unset or null.
    : "${variable:=foo}"
    

    Because of the way Bash handles expansion of this expression, you can safely use this with set -u without getting a “bash: variable: unbound variable” error.

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