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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T15:01:48+00:00 2026-06-09T15:01:48+00:00

I just got into arguments in Python and I find it strange the way

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I just got into arguments in Python and I find it strange the way the arguments system works in Python (I’m not sure about other languages). For example:

from sys import argv

arg1, arg2, arg3 = argv

print "First argument: ", arg1
print "Second argument: ", arg2
print "Third argument: ", arg3

When I run this in command line with the arguments that follow:

python example.py First Second

It gives the output:

First argument: example.py
Second argument: First
Third argument: Second

Does this mean that python starts counting from zero? Or is there some different or some more reasons it does that. It’s odd, but interesting.

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  1. Editorial Team
    Editorial Team
    2026-06-09T15:01:50+00:00Added an answer on June 9, 2026 at 3:01 pm

    Yes, Python uses zero-based indexing as you surmised (and as many other programming languages also do).

    sys.argv is a list of strings.

    sys.argv[0] will contain the name of the script, and subsequent entries in this list of strings will contain command line arguments provided to the script.

    I was going to provide an example, but what you have in your post is as good as I could come up with.

    Finally, as @GregHewgill points out in a helpful comment below, the Python docs provide more information on this as well.

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