I know that may have a few similar questions @stackoverflow, but I didnt found any solution to my problem yet :s
<?php
while($rowVideo = mysql_fetch_array($ResultQueryVideo))
{
?>
<input type="checkbox" name = "checkbox-1[]" class="checkbox" value ="<?php echo $rowVideo['idVideo'] ?>" /> <?php....some code...
This results a few checkbox’s, the same number as idVideo..thats the point.
Now, before the submit, I need to be sure that at least one checkbox is checked. But i was not sucesseful 😡
function isCountCheck (helperMsg) {
var chkCnt = 0;
var Frm = document.forms[0];
var dLen = Frm.length - 1;
for (i=0;i<=dLen;i++) {
if(document.form1.["checkbox-1[]"].checked) chkCnt++;
}
if (chkCnt>0) {
return true;
} else {
alert(helperMsg);
return false;
}
}
Extra details:
form name = “form1”
Can you guide me a litle ?
Thanks
EDIT:
function isCountCheck(){
if($("input[type=checkbox]:checked").length > 0)
{
return true;
}
else
{
alert('Invalid');
return false;
}
}
But still not working..even that alert is shown..
The main problem is that you’re not using the
iindex within the loop to reference the individual checkboxes, and you’ve got a.just before the[which is a syntax error. So change:To:
But you can neaten up the function somewhat as follows:
Demo: http://jsfiddle.net/nnnnnn/ZjK3w/1/
Or just loop through all inputs in the form, checking the type (and/or the name) of each one:
Demo: http://jsfiddle.net/nnnnnn/ZjK3w/2/