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Home/ Questions/Q 8283393
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Editorial Team
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Editorial Team
Asked: June 8, 20262026-06-08T10:43:09+00:00 2026-06-08T10:43:09+00:00

I made a rewrite that rewrote the string, site.com/foo , to site.com/?loc=foo.php . It

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I made a rewrite that rewrote the string, site.com/foo, to site.com/?loc=foo.php. It works fine, but when I enter site.com/foo.php, instead of rewriting to site.com/?loc=foo.php.php, it rewrites to something else that shows site.com/?loc=foo.php except without CSS. I want it to rewrite it as site.com/?loc=foo.php.php.

I have an index.php that reads $loc and includes foo.php.

RewriteCond %{REQUEST_FILENAME} !-f
RewriteCond %{REQUEST_FILENAME} !-d
RewriteRule ^([^/]*)$ ?loc=$1.php

Troubleshoot:

I echoed $loc on index.php and there was no feedback at all. I then echoed $loc on foo.php and found out that $loc was not declared. This leads to the conclusion that site.com/foo.php is not being rewritten for some reason in the above code.

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  1. Editorial Team
    Editorial Team
    2026-06-08T10:43:11+00:00Added an answer on June 8, 2026 at 10:43 am

    The script you have should work fine. Here’s what I tested with.

    Options +FollowSymLinks
    RewriteEngine on
    RewriteCond %{REQUEST_FILENAME} !-f
    RewriteCond %{REQUEST_FILENAME} !-d
    RewriteRule ^([^/]*)$ ?loc=$1.php
    

    This means:

    1) You have another parameter in .htaccess that interferes. Comment out (with #) any lines other than the above. Then pull them back in, one by one (or as few as possible) until you find the culpret.

    2) loc.php actually exists. the -f means “if the file does not exist”

    3) When you generate $loc, you are excluding the varaible for some reason. You can check by adding the top to your index.php file. The first line shows you the get (should be ‘lol’=>’loc.php.php’) and the second line shows you all the confertions that have gone on:

    <?php
      print_r($_GET);
      echo '<br><br>';
      print_r($_SERVER);
    ?>
    
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